Calculate the work done pumping water out of a spherical tank of radius .
Solution
(1) Slice the tank of water into horizontal layers:
Coordinate is at the center of the sphere, increasing upwards.
(2) Calculate weight of single slice:
(3) Work to lift out single slice:
Distance to raise a slice:
Then:
(4) Total work by integrating over all slices:
Note A: The integration runs over all slices, which start at (bottom of tank), and end at (top of tank).
Question: Extra question: what if the spigot sits above the tank?
Question: Extra question: what if the tank starts at just of water depth?
Water pumped from a frustum
Find the work required to pump water out of the frustum in the figure. Assume the weight of water is .
Solution
(1) Find weight of a horizontal slice.
Coordinate at top, increasing downwards.
Use for radius of cross-section circle.
Linear decrease in from to :
Area is :
:
(2) Find work to pump out a horizontal layer.
Layer at is raised a distance of .
Work to raise layer at :
(3) Integrate over all layers.
Integrate from top to bottom of frustum:
Final answer is .
Raising a building
Find the work done to raise a cement columnar building of height and square base per side. Cement has a density of .
Solution
(1) Weight of each layer:
(2) Work to lift layer into place:
(3) Find total work as integral over the layers:
Raising a chain
An chain is suspended from the top of a building. Suppose the chain has weight density . What is the total work required to reel in the chain?
Solution
(1) Compute weight of a ‘link’ (vertical slice of the chain):
(2) Work to raise link to top:
Each link (slice) is raised from height to height 80:
Then:
(3) Integrate over the chain for total work:
Raising a leaky bucket
Suppose a bucket is hoisted by a cable up an tower. The bucket is lifted at a constant rate of and is leaking water weight at a constant rate of . The initial weight of water is . What is the total work performed against gravity in lifting the water? (Ignore the bucket itself and the cable.)
Solution
(1) Compute total force from water :
Choose coordinate at base, at top.
Rate of water weight loss per unit height:
Total water weight at height :
(2) Work to raise bucket by :
(3) Total work by integrating :
Change of method and integral formula!
For this example, we use the formula rather than the formula used in the earlier examples.
This integral sums over the work to lift macroscopic material through each microscopic as if in sequence, and thus represents distance lifted.
Earlier examples summed over the work to lift microscopic material through the macroscope (all the way up).