Geometric sequence: revealing the format

Find a0 and r and an (written in the geometric sequence format) for the following geometric sequences:

(a) an=(−12)n (b) bn=−3(2n+15n)
(c) cn=e5−7n

Solution

(a)

Plug in n=0 to obtain a0=1. Notice that an+1/an=−1/2 and so therefore r=−1/2. Then the ‘general term’ is an=a0⋅rn=1⋅(−1/2)n.


(b)

Rewrite the fraction:

2n+15n≫≫2⋅(25)n

Plug that in and observe bn=−6⋅(2/5)n. From this format we can read off b0=−6 and r=2/5.


(c)

Rewrite:

cn≫≫e5⋅e−7n≫≫e5⋅(e−7)n

From this format we can read off c0=e5 and r=e−7.