A series is called positive when its individual terms are positive, i.e. for all .
The partial sum sequence is monotone increasing for a positive series.
By the monotonicity test for convergence of sequences, therefore converges whenever it is bounded above. If is not bounded above, then diverges to .
Another test, called the integral test, studies the terms of a series as if they represent rectangles with upper corner pinned to the graph of a continuous function.
To apply the test, we must convert the integer index variable in into a continuous variable . This is easy when we have a formula for (provided it doesn’t contain factorials or other elements dependent on integrality).
Integral Test (IT)
Applicability: must be:
Continuous
Positive
Monotone decreasing
Test Statement:
Extra - Integral test: explanation
To show that integral convergence implies series convergence, consider the diagram:
This shows that for any . Therefore, if converges, then is bounded (independent of ) and so is bounded by that inequality. But ; so by adding to the bound, we see that itself is bounded, which implies that converges.
To show that integral divergence implies series divergence, consider a similar diagram:
This shows that for any . Therefore, if diverges, then goes to as , and so goes to as well. So diverges.
Notice: the picture shows entirely above (or below) the rectangles. This depends upon being monotone decreasing, as well as . (This explains the applicability conditions.)
Next we use the integral test to evaluate the family of -series, and later we can use -series in comparison tests without repeating the work of the integral test.
-series
A -series is a series of this form:
Convergence properties:
Extra - Proof of -series convergence
(1) To verify the convergence properties of -series, apply the integral test:
Indeed is continuous and positive and decreasing as increases.
(2) Apply the integral test.
Integrate, assuming :
When we have
When we have
When , integrate a second time:
(3) Conclude: the integral converges when and diverges when .
Supplement: we could instead immediately refer to the convergence results for -integrals instead of reproving them here.
Theory 2
Direct Comparison Test (DCT)
Applicability: Both series are positive: and .
Test Statement: Suppose for large enough .
(Meaning: for with some given .) Then:
Smaller pushes up bigger:
Bigger controls smaller:
Theory 3
Some series can be compared using the DCT after applying certain manipulations and tricks.
For example, consider the series . We suspect convergence because for large. But unfortunately, always, so we cannot apply the DCT.
We could make some ad hoc arguments that do use the DCT, eventually:
Trick Method 1:
Observe that for we have . (Check it!)
But converges, indeed its value is , which is .
So the series converges.
Trick Method 2:
Observe that we can change the letter to by starting the new at .
Then we have:
This last series has terms smaller than so the DCT with (a convergent -series) shows that the original series converges too.
These convoluted arguments suggest that a more general version of Comparison is possible.
Indeed, it is sufficient to compare the relative large-n behavior of the two series. We use the termwise ratios to estimate comparative behavior for increasing .
Limit Comparison Test (LCT)
Applicability: Both series are positive: and .
Test Statement: Suppose that . Then:
If , i.e. finite non-zero, then:
Extra - LCT edge cases
If or , we can still draw an inference, but only in one direction:
If :
If :
Extra - Limit Comparison Test explanation
Suppose and . Then for sufficiently large, we know .
Doing some algebra, we get for large.
If converges, then also converges (constant multiple), and then the DCT implies that converges.
Conversely: we also know that , so for all sufficiently large. Thus if converges, also converges, and by the DCT again converges too.