01
Absolute and conditional convergence
Determine whether the series are absolutely convergent, conditionally convergent, or divergent.
Show your work. You must check applicability of tests.
(a)
(b)
Solution
03
(a)
Therefore it is not absolutely converging. Proceed to the AST.
- Passes SDT? Yes,
. - Decreasing? Yes, denominator is increasing.
Therefore the AST applies and says this converges. So it converges conditionally.
(b)
So this fails the SDT, hence it diverges.
Link to original
02
Absolute and conditional convergence
Determine whether the series are absolutely convergent, conditionally convergent, or divergent by applying series tests.
Show your work. You must check that the test is applicable.
(a)
(b)
Solution
07
(a) We first check for absolute convergence:
This fails the SDT, so the series diverges!
(b) Notice that
. Check for absolute convergence: Then:
Since
Link to originalconverges ( ), the DCT says that converges. So the original series converges absolutely and we are done.
03
Alternating series: error estimation
Find the approximate value of
such that the error satisfies . How many terms do you really need?
Solution
08
We use the alternating series test error bound formula. (AKA: “Next Term Bound”)
We seek the smallest
such that . What that happens, we will have: Our formula for
: We cannot easily solve for
to provide , so we just start listing out the terms: We see that
Link to originalis the first term less than 0.005, so and we need the first 5 terms.