To understand the ratio test better, first consider this series:
The term is created by multiplying the prior term by .
The term is created by multiplying the prior term by .
The term is created by multiplying the prior term by .
When , the multiplication factor giving the next term is necessarily less than . Therefore, when , the terms shrink faster than those of a geometric series having . Therefore this series converges.
Similarly, consider this series:
Write for the ratio from the prior term to the current term . For this series, .
This ratio falls below when , after which the terms necessarily shrink faster than those of a geometric series with . Therefore this series converges.
The main point of the discussion can be stated like this:
Whenever this is the case, then eventually the ratios are bounded below some , and the series terms are smaller than those of a converging geometric series.
Extra - Ratio Test proof
Let us write for the ratio to the next term from term .
Suppose that as , and that . This means: eventually the ratio of terms is close to ; so eventually it is less than .
More specifically, let us define . This is the point halfway between and . Since , we know that eventually .
Any geometric series with ratio converges. Set for big enough that . Then the terms of our series satisfy , and the series starting from is absolutely convergent by comparison to this geometric series.
(Note that the terms do not affect convergence.)
Theory 2
Root Test (RooT)
Applicability: Any series.
Test Statement:
Suppose that as .
Then:
Extra - Root test: explanation
The fact that and implies that eventually for all high enough . Set (the midpoint between and ).
Now, the equation is equivalent to the equation .
Therefore, eventually the terms are each less than the corresponding terms of this convergent geometric series: