Find the Taylor series for the function centered at .
Solution
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Calculate derivatives. Use .
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Each new derivative takes down the next power as a factor, and switches the sign. The accumulation of powers follows a factorial pattern, and these factorials cancel those added to the denominator to make .
So we have:
Alternate method:
We can derive this Taylor series using some algebraic tricks with the standard geometric series:
Discovering the function from its Maclaurin series
For each of these series, identify the function of which it is the Maclaurin series, and evaluate the function at an appropriate choice of to find the total sum for the series.