Frank is a competitive hot dog eater. He eats in with .
What is the probability that Frank manages to consume in or less, in an upcoming competition? Use a normal approximation from the CLT to estimate this probability.
State the reason that the normal approximation is applicable.
Solution
04
(1) The normal approximation in this case is applicable since:
Assumptions:
Frank eats a large number of hot dogs the sample size, or , is sufficiently large
We assume that the amount of time Frank spends on each hot dog does not depend on how many he has had previously the times to consume each hot dog are independent and identically distributed
(2) Let be the time taken to eat the -th hot dog. Let be the time taken to eat hot dogs. Then seconds with seconds.
Use a normal approximation to estimate the probability that exactly 100 outcomes are either 3 or 6.
Do this with and without the continuity correction.
03
Normal approximation - Ventilator filters
A mechanical ventilator model uses air filters that last 100 hours on average with a standard deviation of 30 hours.
How many filters should be stocked so that the supply lasts 2,000 hours with probability at least 95%? Use a normal approximation to estimate the answer.
State the reason that the normal approximation is applicable.
Solution
06
In this case the normal approximation is applicable since we have a large sample size (need a large number of filters to last hours) and they follow follow independent but identical distributions.
Let be how long the -th filter lasts. Let where we want to find such that . By normal approximation and the Central Limit Theorem, we have
An instructor has 50 exams to grade. The grading time for each exam follows a distribution with an average of 20 minutes and variance of 16. Assume the grading times per exam are independent.
Roughly what are the odds that after 450 minutes of grading, at least half the exams will be graded? Use a normal approximation to estimate the answer.
State the reason that the normal approximation is applicable.
A class has 40 students: 24 women and 16 men. Each period the teacher selects a random student to present an exercise on the board from among those who have not presented already.
Let count the number of times a man was chosen after 15 class periods.
(a) Find .
(b) Find .
Hint: Is independent of ? Do you know anyway?
Solution
08
(a)
Let be the indicator that a man was chosen in the -th period. Then for each , and the are independent for each . Let be the total number of times a man was chosen. We can use a similar argument to Problems 2 or 3, or we can simply use linearity of expectation:
(b)
(1) Using the standard formula for the variance of a sum of random variables, we have:
Since the variables are identically distributed, their variances are equal. Thus,
(2) Now, the sum has terms, and since each is identically distributed, each term is identical. Thus,
for some fixed .
(3) We then have
Finally, , and thus
Plugging these values in, we have .
Let be independent RVs each having the following PMF:
Notice that and for each .
Define . So and , and therefore .
By the CLT, should converge to the standard normal distribution as . In this problem you explore the limit process by direct computation of the cases .
(a) Compute the PMF of in terms of .
Hint steps:
is the number of sequences of outcomes of having a total sum of , times the probability of any particular such sequence.
Find the probability of any particular sequence of outcomes of .
There are ways to get outcomes of and outcomes of . Solve for in terms of .
Put 2. and 3. together in 1. to get your formula.
(b) Compute the PMF of for using your formula from (a) together with a scaling (derived variable calculation).
(c) Draw the graphs of the PMF of and the PMF of for .
07
Normal approximation of the binomial - Double ones
Roll a pair of dice 10,000 times. Estimate the odds that the number of “snake eyes” (double ones) obtained is in the range .
08
Normal approximation - Heads v. tails
Flip a coin 10,000 times. Let measure the number of heads, and measure the number of tails. Estimate the probability that and are within 100 of each other.
Hint: Write an inequality for the condition, then sub a formula for in terms of .
Solution
07
Let and be the number of heads and tails respectively. Then we have the following two conditions:
Thus, .
Let be the event that the -th flip is a head. Then for each and .
Thus, by CLT, .
By the normal approximation, using the continuity correction, we have:
A 100 Watt light bulb’s expected lifetime is 600 hours, with variance 360,000. An advertising board uses one of these light bulbs at a time, and when one burns out, it is immediately replaced with another. (The lifetime of each bulb is independent from the others.) Let the continuous random variable be the total number of hours of advertising from 10 bulbs.
(a) Find the expected value of .
(b) Find the variance of .
(c) Use the CLT to approximate the probability that is less than 5,500 hours. (You should decide whether it is appropriate to use the continuity correction.)
Suppose a lottery game requires that you purchase a $10 game card and advertises a 10% probability of winning a prize.
Use the Central Limit Theorem and the continuity correction to approximate the probability of winning at least 20 times when you purchase 100 of these game cards.