Events and outcomes

02 - Coin flipping: counting subsets

There are possible sequences, so .

To count the number of possible subsets, consider that we have 32 distinct items, and a subset is uniquely determined by the binary information – for each item – of whether it is in or out. Thus there are possibilities. So .

Conditional probability

07 - Simplifying conditionals

    • Definition of ‘conditional’:
    • The problem assumes that . Therefore .
    • Therefore, answer: .
    • Definition of ‘conditional’:
    • Since , we know .
    • Therefore and answer .
    • Definition of ‘conditional’:
    • Since , we have .
    • Therefore, answer .
    • Definition of ‘conditional’:
    • There is no way to simplify further.
    • We could write if desired.

09 - Division into Cases

  1. & Label events.
    • Event : a red marble is transferred
    • Event : a green marble is transferred
    • Event : a red marble is drawn from Bin 2
    • Event : a green marble is drawn from Bin 2
    • Answer will be .
  2. !! Division into Cases.
    • General formula:
    • We seek , use
    • Use and therefore
    • So we use:
  3. && Plug in data and compute the answer.
    • Know
    • Know
    • Know
    • Know
    • Therefore:

11 - Inferring bin from marble

  1. & Label events.
    • Event : friend chooses Bin 1
    • Event : friend chooses Bin 2
    • Event : friend draws a red marble
    • Event : friend draws a green marble
    • Answer will be
  2. && Identify knowns.
    • Know
    • Know
    • Know
    • Know
    • Know
  3. !! Translate Bayes’ Theorem
    • Bayes’ Theorem for :
    • Division into Cases for the denominator:
  4. && Plug in data and compute the answer.
    • Denominator:
    • Desired event:

12 - Independence and complements

(1) We show that

  1. &&& Assume and show .
    • Divide into the cases:
    • Apply the assumption:
    • Algebra:
    • Negation rule:
  2. & Assume and show
    • !! In the above sequence, apply this assumption to break up the second term instead.

(2)

  1. & Show that and are equivalent.
    • ! In the first equivalence, replace with and with . Use too.

Counting

15 - Counting teams with Cooper

There are teams that include Cooper, and teams in total. So we have:

18 - Counting out 3 teams

This is just the multinomial coefficient with this data:

174445
So we have:

Expectation and variance

27 - Gambling game - tokens in bins

  1. & Setup.
    • Let be a random variable measuring your winnings in the game.
    • The possible values of are 1, 50, and 1000.
  2. && Find PDF .
    • For have
    • For have
    • For have
    • These add to 1, and for all other .
  3. && Find .
    • Using the discrete formula:
  4. & Conclusion
    • Since , if you play it a lot at $50 you will generally make money.
  • Challenge Q:
    • If you start with $200 and keep playing to infinity, how likely is it that you go broke?

Function on a random variable

36 - Probabilities via CDF

(a)

(b) Same as (a) because (single point in a continuous distribution).

(c)

(d)