(a) a3=S3−S2≫≫(5−232)−(5−222)≫≫−29+24≫≫518 (b) an=Sn−Sn−1≫≫(5−2n2)−(5−2(n−1)2)≫≫2(n−1)2−2n2≫≫2n2−2(n−1)2n2(n−1)2≫≫2n2−2(n2−2n+1)n2(n−1)2≫≫4n−2n2(n−1)2 When n=1, this formula is undefined, because S0 is undefined. But we know that: a1=S1≫≫5−212≫≫3 (c) Simply take the limit of SN as N→∞: SN⟶n→∞S5−2N2⟶n→∞5