(a) sinu=∑n=0∞(−1)nu2n+1(2n+1)!≫≫sin(3x2)=∑n=0∞(−1)n(3x2)2n+1(2n+1)!≫≫∑n=0∞(−1)n32n+1(2n+1)!x4n+2 (b) eu=∑n=0∞unn!≫≫e5x=∑n=0∞(5x)nn!≫≫x2e5x=∑n=0∞5nn!xn+2