(a)

sinu=n=0(1)nu2n+1(2n+1)!sin(3x2)=n=0(1)n(3x2)2n+1(2n+1)!n=0(1)n32n+1(2n+1)!x4n+2

(b)

eu=n=0unn!e5x=n=0(5x)nn!x2e5x=n=05nn!xn+2