(a)

n=0(1)nπ2n+142n+1(2n+1)!n=0(1)n(π/4)2n+1(2n+1)!sinx|x=π/422

(b)

n=022nn!n=0(4)nn!ex|x=4e4

(c)

n=0(1)nπ2n+232n+1(2n)!π23n=0(1)n(π/3)2n(2n)!π23cosx|x=π/3π26