(1) Find the PMF of X from the CDF:

k0123
PX(k)0.10.10.30.5

(2) Find the PMF of Y=3X:

Since Y=3X, the possible values of Y are 30=0, 31=3, 32=6, 33=9, each with the same probability as the corresponding X value.

k0369
PY(k)0.10.10.30.5