(a)

L follows a Pascal distribution with parameters p=0.2 and =5.


(b)

Compute PL(10):

PL(10)=(k11)(1p)kp(94)(0.8)5(0.2)50.0132

(c)

Compute P[L7]:

The minimum number of passersby before a winner is declared is 5, so P[L7]=1PL(5)PL(6).

P[L7]=1PL(5)PL(6)1(44)(0.8)0(0.2)5(54)(0.8)1(0.2)50.9984