Find the total force on the submerged vertical plate that is an isosceles triangle with (bottom) base and height , and assume it is submerged with the upper vertex below the surface. Liquid is oil with density .
Set up an integral that expresses the work done (against gravity) to build a circular cone-shaped tower of height and base radius out of a material with mass density .
Solution
04
(1) Integral formula:
Option 1:
(2) Setup:
Set at the bottom, increasing upwards.
Radius of the cone with a QLIF:
Horizontal slice of the cone tower: disk of radius at height , satisfies:
The slice at is raised a distance of .
Thus:
Option 2:
(2) Setup:
Set at the top of the cone, increasing downwards.
Now is the distance from the ground up to the height of a slice indexed by .
A bucket of water is raised by a chain to the top of a -foot building. The water is leaking out, and the chain is getting lighter.
The bucket weighs , the initial water weighs , and the chain weighs , and the water is leaking at a rate of as the bucket is lifted at a constant rate of .
What is the total work required to raise the bucket of water?
Solution
08
(1) Integral formula:
Let at the ground and increase going up.
(2) Compute force:
The force on the rope (at the top) when the bucket is at height is:
A cylindrical tank is full of water and the water is pumped out the top. (See figure.) The length of the tank is and the radius is .
(a) Set up an integral for the total work performed assuming the tank is initially completely full.
(b) Set up an integral for the total work performed assuming the tank is initially full to and the water is pumped out of a spigot extending above the top of the tank.
Solution
09
(1) Integral formula:
Set at the center of the tank.
(a)
(2) Geometry:
So:
Tank length is so a horizontal slice is a rectangle with area .
The Great Pyramid of Giza is tall and has a square base with on each side. It is built of stone with mass density .
Set up an integral that expresses the work (against gravity) required to build the pyramid.
Solution
10
(1) Integral formula:
(2) Integrand components:
Option 1:
Set at the base, going up.
Take a cross-sectional slice with a vertical plane. This intersects the surface of the pyramid in a triangle whose width is the side length of the square (the horizontal cross section) at height .