Due date: Thursday 1/22, 11:59pm
Trig power products
01
01
Link to originalSomewhat odd power product
Compute the integral:
Solution
Solutions - 0040-01
(1) Notice odd power on
. Swap the even bunch:
(2) Integrate with
-sub setting and thus : Link to original
02
02
Link to originalTangent and secant both even
Compute the integral:
Solution
Solutions - 0040-02
Notice
. Therefore integrate with -sub setting and : Link to original
03
03
Link to originalAll even power product
Compute the integral:
Solution
Solutions - 0040-03
(1) Notice all even powers. Use power-to-frequency conversion:
Plug in:
Simplify:
(2) Reduce power again for
: (This is derived from the power-to-frequency formula by changing ‘
’ to ‘ ’ in that formula.)
(3) On the last term, swap even bunch:
Plug all in and obtain:
(4) Integrate the first three terms:
(5) Integrate the last term with
-sub, setting and :
(6) Combine in final result:
Note: It is also possible to rewrite
Link to originalusing trig identities. So, equally valid answers may look different than this.
Trig substitution
04
01
Link to originalTrig sub
Compute the definite integral:
Solution
Solutions - 0050-01
(1) Substitute
and thus . Adjust the bounds as follows: Rewrite the integral:
(2) Use power-to-frequency conversion:
Note A: Use
Link to original, then and this equals for .
05
02
Link to originalTrig sub
Compute the integral:
Solution
Solutions - 0050-02
(1) Trig substitution. Notice
, so we should make use of the identity . Pick
and thus . Then:
Plug in:
(We assume that
for the relevant values of .)
(2) Perform integration.
Either recall from memory, or multiply above and below by
, and obtain:
(3) To convert to
we need given that . Draw triangle expressing
:
Therefore
. We already know . Thus:
(4) Simplify with log rules:
Link to original
